stop x
2:3
2części zlota
3 części srebra
5 części razem
2/5 x ilość zlota w stopie x
stop y
3:7
3 częsci zlota
7 częsci srebra
10 częsci razem
3/10 y ilośc zlota w stopie y
nowy stop
a)
8kg masa stopu
5:11
5 częsci zlota
11 częsci srebra
16 części razem
5/16 *8kg=5*8/16kg=5/2=2,5 kg ilość zlota w nowym stopie
b)
2/5 x+3/10 y =0,4x+0,3y
c)
x+y=8
0,4x+0,3y=2,5
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