#include <iostream>
using namespace std;
void afisare(int sol[], int lg){
for(int j = 1; j <= lg; ++j)
cout << sol[j] << ' ';
cout << endl;
}
void bkt(int s, int n, int i, int sol[])
{
for(int j = 1; j <= n; ++j)
{
sol[i] = j;
if(s + j <= n)
{
if(s + j == n)
afisare(sol, i);
else
bkt(s + j, n, i+ 1, sol);
}
}
}
int main()
{
// se da un numar n natural sa se afiseze toate perechile de numere posibile care insumate dau numarul n (ordinea nu conteaza)
int n, s = 0, sol[100]; cin >> n;
bkt(s, n, 1, sol);
return 0;
}
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