#include<stdio.h>
int main() {
char line[100];
int i, j, num, count=0;
char vowels[11] = "aeiouAEIOU";
printf("Enter a string: ");
gets(line);
for (i = 0; line[i] != '\0'; i++);
num = i;
for(i = num-1; i >= 0; i--) {
printf("%c", line[i]);
}
printf("\nThe vowels are:");
for(i=0; line[i]!='\0'; i++)
{
for(j=0; vowels[j]!='\0'; j++)
{
if(line[i]==vowels[j])
{
count++;
printf("%c",line[i]);
}
}
}
printf("\nNumber of vowels = %d", count);
return 0;
}
Replies to Re: CSE 2.1 CL2 
Title |
Name |
Language |
UNIX |
When |
Re: Re: CSE 2.1 CL2 |
CL5 |
text |
1695291421 |
1 Year ago. |
CL5 |
DW |
text |
1694688669 |
1 Year ago. |
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